# The first and the

To prove: sum of the nth term from the beginning and the nth term from the end is a + l

We know, an = a + (n – 1)d where a is first term or a1 and d is the common difference, and n is any natural number, and nth term from the end is an = l – (n – 1)d

Now,

an + an = a + (n – 1)d + l – (n – 1)d

an + an = a + nd – d + l – nd + d

an + an = a + l

Hence Proved

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