Q. 2

# Three numbers are

Given: sum of first three terms is 27

To find: the first three terms of AP

Assume the first three terms are a - d, a, a + d where a is the first term and d is the common difference

So, sum of first three terms is a - d + a + a + d = 27

3a = 27

a = 9

given that the product of three terms is 648

so a3 - ad2 = 648

substituting a = 9

93 - 9d2 = 648

729 - 9d2 = 648

81 = 9d2

d = 3 or d = - 3

hence the given terms are a - d, a, a + d which is 6, 9, 12 or 12, 9, 6

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