Answer :

Given: sum of first three terms is 27


To find: the first three terms of AP


Assume the first three terms are a - d, a, a + d where a is the first term and d is the common difference


So, sum of first three terms is a - d + a + a + d = 27


3a = 27


a = 9


given that the product of three terms is 648


so a3 - ad2 = 648


substituting a = 9


93 - 9d2 = 648


729 - 9d2 = 648


81 = 9d2


d = 3 or d = - 3


hence the given terms are a - d, a, a + d which is 6, 9, 12 or 12, 9, 6


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