Q. 135.0( 2 Votes )

# Mark the correct

Answer :

Let 4 numbers of A.P. be the a, a+d, a+2d, a+3d.

Here, given that their sum is 50.

i.e. a+a+d+a+2d+a+3d=50

4a+6d=50

2a+3d=25_____(1)

Also, given that the greatest number is 4 times the least.

i.e.4a=a+3d

3a=3d

a=d

Substituting a=d in (1) we get,

5a=25

a=5

And, d=a=5

So, numbers are a=5;a+d=5+5;a+2d=5+2(5);a+3d=5+3(5)

i.e. 5,10,15,20

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation view all courses RELATED QUESTIONS :

There are n A.M.sRD Sharma - Mathematics

If x, y, z are inRD Sharma - Mathematics

Insert 7 A.M.s beRD Sharma - Mathematics

The 10th</suRD Sharma - Mathematics

Insert five numbeRD Sharma - Mathematics

The 4th</supRD Sharma - Mathematics

Insert 4 A.M.s beRD Sharma - Mathematics

Show that x2RD Sharma - Mathematics

An A.P. consists RD Sharma - Mathematics

How many terms arRS Aggarwal - Mathematics