Answer :

Let 4 numbers of A.P. be the a, a+d, a+2d, a+3d.


Here, given that their sum is 50.


i.e. a+a+d+a+2d+a+3d=50


4a+6d=50


2a+3d=25_____(1)


Also, given that the greatest number is 4 times the least.


i.e.4a=a+3d


3a=3d


a=d


Substituting a=d in (1) we get,


5a=25


a=5


And, d=a=5


So, numbers are a=5;a+d=5+5;a+2d=5+2(5);a+3d=5+3(5)


i.e. 5,10,15,20

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