Answer :

We know Sn=Sn-2+an-1+an



Also, Sn-1=Sn-2+an-1



Now, d=Sn-kSn-1+Sn-2

= Sn-2+2a+2nd-3d-k(Sn-2+a+nd-2d)+Sn-2


Comparing coefficient of both the side we get,

2-k=0 and 2k-3=1


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