Answer :

Here, log 2, log(2x-1) and log(2x+3) are in A.P.


So, log(2x-1)-log2=log(2x+3)-log(2x-1)





Let 2x=y


Then above equation is written as


(y-1)2=2(y+3)


y2-2y+1=2y+6


y2-4y-5=0


(y-5)(y+1)=0


y=5 or y=-1


2x=5 or 2x=-1


x=log25 or 2x=-1 is not possible


x=log25


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