# There are 2

Given: total trees are 25 and equal distance between two adjacent trees are 5 meters

To find: the total distance the gardener will cover

As gardener is coming back to well after watering every tree

Distance covered by him to water 1st tree and return to the initial position is 10m + 10m = 20m

Now, distance between adjacent trees is 5m

Distance covered by him to water 2nd tree and return to the initial position is 15m + 15m = 30m

Distance covered by the gardener to water 3rd tree return to the initial postion is 20m + 20m = 40m

Hence distance covered by the gardener to water the trees are in A.P

A.P. is 20, 30, 40 ………upto 25 terms

Here first term,a = 20,common difference, d = 30 – 20 = 10

And n = 25

We need to find S25 which will be the total distance covered by gardener to water 25 trees

Formula used: where a is first term, d is common difference and n is number of terms in an A.P.

Therefore,    S25 = 25(140)

S25 = 3500

Hence, total distance covered by gardener to water trees is 3500 m

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