Q. 103.9( 54 Votes )

A 12pF capacitor

Answer :

Given, C = 12 pF = 12 x 10^-12 F

V = 50 V

The electrostatic energy stored in the capacitor,

W = (1/2) CV² = (1/2) × 12 × 10^-12 × (50)² = 1.5 × 10^-8 J

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