Answer :

Given, q = 1.6 x 10-7 C

Radius of the sphere, r = 12 cm = 0.12 m

(a) Inside the sphere: The charge on a conductor resides on its outer surface. Therefore, electric field inside the sphere is zero.

(b) Just outside the sphere: For a point on the charged spherical conductor or outside it, the charge may be assumed to be concentrated at its center.

Therefore, the electric field just outside the sphere is given as:

where, q is the charge due to which the field is being calculated

putting the values of “r” and “q” in the equation, we get,

E = 105 N/C

(c) At a point 18 cm from the center: Given, R = 18 cm

Electric field at a point 18 cm from the center

E = 4.4 x 104 N/C

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses

(i) Use Gauss's lPhysics - Board Papers

(a) Draw equipotePhysics - Board Papers

Draw the equipotePhysics - Board Papers

Draw the pattern Physics - Board Papers

Answer carefully:NCERT - Physics Part-I

A spherical conduNCERT - Physics Part-I