Answer :

The system of two protons and electron is represented as below,



The total potential energy at infinity is Zero.


Thus, Potential energy of the system is,


V =


Where,


Charge on proton 1, q1 = 1.6 × 10-19 C


Charge on proton 2, q2 = 1.6 × 10-19 C


Charge on electron, q3 = - 1.6 × 10-19 C


Distance between proton 1 and proton 2, d1 = 1.5 × 10-10 m


Distance between proton 1 and electron, d2 = 1 × 10-10 m


Distance between proton 2 and electron, d3 = 1 × 10-10 m


ϵ0 = Permittivity of free space


and,


V =



V = -30.7 × 10-19 J


Writing in electron volts, we get,


V = -19.2 eV


( 1eV = 1.6 × 10-19 J)


Therefore, the potential energy of the system is -19.2 eV.


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