# If one of the two

The system of two protons and electron is represented as below,

The total potential energy at infinity is Zero.

Thus, Potential energy of the system is,

V =

Where,

Charge on proton 1, q1 = 1.6 × 10-19 C

Charge on proton 2, q2 = 1.6 × 10-19 C

Charge on electron, q3 = - 1.6 × 10-19 C

Distance between proton 1 and proton 2, d1 = 1.5 × 10-10 m

Distance between proton 1 and electron, d2 = 1 × 10-10 m

Distance between proton 2 and electron, d3 = 1 × 10-10 m

ϵ0 = Permittivity of free space

and,

V =

V = -30.7 × 10-19 J

Writing in electron volts, we get,

V = -19.2 eV

( 1eV = 1.6 × 10-19 J)

Therefore, the potential energy of the system is -19.2 eV.

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