# Two charges 5 × 10–8 C and –3 × 10–8 C are located 16 cm apart. At what point(s) on the line joining the two charges is the electric potential zero,Take the potential at infinity to be zero.

Given,

Two charges qA = 5 x 10-8 C and qB = -3x10-8 C

Distance between two charges, r = 16 cm = 0.16 m

Consider a point O on the line joining two charges where the electric potential is zero due to two charges. From the figure we can see that, x = distance of point O from charge qA

Electric potential at point O due to qA,   ϵ0 is the permittivity of free space. Its value is 8.85 x 10-12 F/m

Electric potential at point O due to qB   Since the total electric potential at O is zero,

VA + VB = 0   On cross multiplying we get,

5 × (0.16 -x) = 3x

0.8 – 5x = 3x

8x = 0.8

x = 0.1 m = 10 cm(from charge qA)

at a distance of 10 cm from the positive charge, the potential is zero between the two charges.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.