Answer :

Given,

Two charges qA = 5 x 10-8 C and qB = -3x10-8 C



Distance between two charges, r = 16 cm = 0.16 m




Consider a point O on the line joining two charges where the electric potential is zero due to two charges.





From the figure we can see that, x = distance of point O from charge qA




Electric potential at point O due to qA,





ϵ0 is the permittivity of free space. Its value is 8.85 x 10-12 F/m




Electric potential at point O due to qB







Since the total electric potential at O is zero,




VA + VB = 0





On cross multiplying we get,


5 × (0.16 -x) = 3x


0.8 – 5x = 3x


8x = 0.8




x = 0.1 m = 10 cm(from charge qA)


at a distance of 10 cm from the positive charge, the potential is zero between the two charges.





Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

Define an equipotPhysics - Board Papers

Describe schematiNCERT - Physics Part-I

Figure 2.34 showsNCERT - Physics Part-I

Two charges –q anNCERT - Physics Part-I

A charge 'q' is mPhysics - Board Papers

(a) Draw the equiPhysics - Board Papers

A regular hexagonNCERT - Physics Part-I

Two charges 2 <spNCERT - Physics Part-I

In a hydrogen atoNCERT - Physics Part-I