Answer :

Potential difference of a parallel plate capacitor(V) = 1kV = 1000V


Dielectric constant of a material(ϵr) = 3


Dielectric strength = 107V/m


Electric field intensity(E) = 10%of 107


E = 106V/m


(since, the field intensity never exceeds 10% of the dielectric strength)


Capacitance of the parallel plate capacitor(C) = 50pF = 50 × 10-12F


Distance between the plates (d),



d = 10-3m


Capacitance =


where, ϵ0 = Permittivity of free space = 8.85 × 10-12N-1 m-2 C2


A = area of plates



A = 50 × 10-12F × 10-3m/8.85 × 10-12N-1 m-2 C2 × 3


A = 1.88 × 10-3m2


Minimum area of the plates required = 1.88 × 10-3m2


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