Answer :

Area of the plates of a parallel capacitor (A) = 90cm2 = 910-3m

Distance between the plates (d) = 2.5mm = 2.510-3m


Potential difference across the plates (V) = 400V


(a) Electrostatic energy stored in the capacitor(E) = CV2


Since, Capacitance (C) =



Where, = Absolute Permittivity of free space = 8.8510-12C2N-1m-2



E = 2.5510-6J


The electrostatic energy stored by the capacitor = 2.5510-6J


(b) Volume between plates of capacitor (v) = A × d


= 910-3m2 × 2.510-3m


= 2.2510-5m3


Therefore, Energy per unit volume (u) = E/v




The energy per unit volume (u) = 0.113 Jm-3


Relation between u and the magnitude of electric field E between the plates


Since,


Energy per unit volume (u) = E/v


= CV2 /v


Here, V = voltage across capacitor


v = volume between plates of capacitor,




Here, V/d is the Electric intensity or Electric field so,


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