Q. 294.0( 1 Vote )

# The two rods show

Let’s take first condition – Since, rods are connected in series, rate of heat flow remains constant. = = constant

Where

∆T = is change in temperature between the two sides of the rods.

A= Area of cross section of the rods

K = thermal conductivity of the rods

L = length of the rod

Hence = Where ,

KA , KB are thermal conductivity of rod A and B

30 KA = 70 KB ……………………………(1)

Now, in second condition, the rods are interchanged as shown in fig below – Let x°C be the unknown temperature of the junction AB

Now, since rate of heat flow remains constant- = That gives

100 B - x B = A x

Substituting for A from(1) and solving the above equation

100 = x +x

x = 30°C

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