Answer :


Given:
Thickness of the container : x = 1 cm = 0.01 m
Thermal conductivity of the sheet : K= 0.025 J s–1m–1°C–1
Temperature of the liquid nitrogen: T1 = 80 K
Area of the container : A = 0.8 m2
Temperature of the atmosphere : T2 = 300 K
Formula used:
Rate of amount of heat flowing is given as:

Here, Δθ is the amount of heat transferred, ΔT is the temperature difference, K is the thermal conductivity of the material, A is the area of cross section of the material and x is the thickness of the material.
Here, ΔT = T2- T1 = 220 K
Substituting the values we get,


Hence,
the rate of heat flow from the atmosphere to the liquid nitrogen is 440 J/s.


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

Assume that the tHC Verma - Concepts of Physics Part 2

Calculate the amoHC Verma - Concepts of Physics Part 2

A rod of negligibHC Verma - Concepts of Physics Part 2

Seven rods A, B, HC Verma - Concepts of Physics Part 2

Four identical roHC Verma - Concepts of Physics Part 2

Find the rate of HC Verma - Concepts of Physics Part 2

The three rods shHC Verma - Concepts of Physics Part 2

The two rods showHC Verma - Concepts of Physics Part 2

A room has a windHC Verma - Concepts of Physics Part 2

A semicircular roHC Verma - Concepts of Physics Part 2