Q. 10

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Answer :

Given:
Length of the rod: x = 20 cm =0.2 m
Area of cross section of the rod: A = 0.2 cm2 = 0.2× 10-4 m2.
Temperature at left end : T2 = 20° C
Temperature at right end : T1 = 80° C
Thermal conductivity of copper: K = 385 W m–1 °C–1. Distance of point C from left end : x’ = 11cm = 0.11 m
Formula used:
(b)
Rate of amount of heat flowing or heat current is given as: Here, Δθ is the amount of heat transferred, ΔT is the temperature difference, K is the thermal conductivity of the material, A is the area of cross section of the material and x is the thickness or length of the material.
Transfer of heat due to entire rod is,  Hence, heat current in the rod is 2.31 J/s
(a)
Let T be the temperature at point C.
T>T2 as heat flows from High temperature to low temperature.
Substituting we get,     Hence, temperature at a distance of 11 cm from the left end is 53 °C.

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