Q. 335.0( 1 Vote )

Find the rate of heat flow through a cross-section of the rod shown in figure (θ2> θ1). Thermal conductivity of the material of the rod is K.

Answer :

Let’s redraw the diagram

From the above diagram we can say that ΔABE is similar to ΔACD.

By the property of similar triangles-


x = r1 + (r2 – r1 )

Lets assume-

a =

r = ax + r1 (1)

Thermal resistance is given by –

dR =

Now area

dR =

dR =


Solving above integral

R =

R =

Rate of heat flow =

q = Kπr1r2

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