Answer :

Given-
Area of the body, A = 1.6 m2


Temperature of the body, T = 310 K
We know from Stefan-Boltzmann law, we have-


= σAT4


Where,


A is the area of the body


σ is the Stefan-Boltzmann constant


σ = 6 × 10−8 W m−2 K−4.


Therefore,


Energy radiated per second = 1.6 × 6 × 10−8 × (310)4
= 886.58


≈887 J


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