Q. 653.8( 5 Votes )
The current
Answer :
Given:
Rate of variation of current = 0.01 A s–1.
No of turns/m (n) = 2000
Radius(r) = 6 cm = 0.06 m
Formula used:
(a) Radius of circle(r’) = 1 cm = 0.01 m
Time(t) = 2 s
For two seconds, change of current = (2 x 0.01 A.) = 0.02 A
Magnetic flux , where B = magnetic field, A = area
Area of circle
Magnetic field of a solenoid , where μ0 = magnetic permeability of vacuum, n = number of turns per unit length, Δi = change in current
Hence, flux =
⇒ Wb
Hence, in 1 second =
Wb (Ans)
(b) =
, where E = electric field, dr = line element, E’ = emf,
= flux, t = time
Hence, in this case, this becomes
, where r = radius of circle
⇒ Vm-1(Ans)
(c) For the point located outside,
Wbs-1
= flux, t = time, μ0 = magnetic permeability of vacuum, n = number of turns per unit length, di/dt = rate of change in current
⇒
, where E = electric field, r = radius of circle(since
)
Hence,
⇒ Vm-1 (Ans)
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A uniform m
HC Verma - Concepts of Physics Part 2The current
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HC Verma - Concepts of Physics Part 2The current
HC Verma - Concepts of Physics Part 2