Answer :


Given:


Length of the wire=10cm


Angle of length of wire with velocity=60°


Magnetic field intensity=1.0T


Speed of wire v=20cm/s =0.2m/s


(a) we know that,


motional emf produced due to a conductor of length l moving with velocity v in a magnetic field B is given by



It is given that plane of motion is perpendicular to electric field i.e. angle between v and B =90°


And the angle between velocity and length of wire=60°




We take only that component of length vector which is perpendicular to velocity vector


Putting the values of B, v, l we get



Therefore the emf induced in the rod is


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