Q. 605.0( 2 Votes )

# Consider th

Given:

Resistance of circular loop = R

AOC = 90°

Angular velocity = w

Formula used:

From the previous problem, emf … (i), where B = magnetic field, w = angular velocity, a = radius

Now, since AOC = 90°, the major and minor segments of the arc AC consist of parallel combination of resistances of R/4 and 3R/4 respectively (since the resistance is divided in the ratio of the angle at the centre).

Hence, equivalent resistance =

Therefore, current through the rod , where E = emf, R’ = equivalent resistance

= (Ans)

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