Answer :

Given:


Rate of variation of current = 0.01 A s–1.


No of turns/m (n) = 2000


Radius(r) = 6 cm = 0.06 m


Formula used:


(a) Radius of circle(r’) = 1 cm = 0.01 m


Time(t) = 2 s


For two seconds, change of current = (2 x 0.01 A.) = 0.02 A


Magnetic flux , where B = magnetic field, A = area


Area of circle


Magnetic field of a solenoid , where μ0 = magnetic permeability of vacuum, n = number of turns per unit length, Δi = change in current


Hence, flux =


Wb


Hence, in 1 second = Wb (Ans)


(b) = , where E = electric field, dr = line element, E’ = emf, = flux, t = time


Hence, in this case, this becomes


, where r = radius of circle


Vm-1(Ans)


(c) For the point located outside,


Wbs-1


= flux, t = time, μ0 = magnetic permeability of vacuum, n = number of turns per unit length, di/dt = rate of change in current


, where E = electric field, r = radius of circle(since )


Hence,


Vm-1 (Ans)


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