Q. 244.3( 3 Votes )

Write the argumen

Answer :

As we know that,


arg (z1z2) = arg(z1)+arg(z2) so,


arg (z1z2z3) = arg(z1)+arg(z2)+arg(z3)


arg((1+√3 i)(1+i)(cos θ+ i sin θ)


= arg(1+√3 i)+arg(1+i)+arg(cos θ + i sin θ).......... (1)



arg(z1 ) = θ



z2 = arg(1+i)






z3 = arg(cos θ + i sin θ)


1(cos θ + i sin θ)


arg(z3 ) = θ


In r(cos θ + i sin θ) , arg(z) = θ


By putting the value of all arg in 1, we get



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