Q. 37

# Mark the Correct

If z = a + ib lies in third quadrant then a and b both are less than zero

a2 – b2 < 0 and ab > 0 because a2 + b2 is always greater than zero

(a – b)(a + b) < 0

Here a and b both are less than zero that means (a + b) is always less than zero

So, a – b > 0 a > b

Then, final answer is b < a < 0

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