Q. 225.0( 1 Vote )

# If |z + 1| = z +

Given:

|z+1|=z+2(1+i)

Let us assume z=x+iy

|x+iy+1|=x+iy+2+2i

Equating Real and Imaginary parts on both sides

y+2=0

y=-2----------------(1)

(x+1)2+y2=(x+2)2

x2+2x+1+(-2)2=x2+4x+4

2x=1+4-4

2x=1

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