Answer :

Let, z = 2i

Let 0 = rcosθ and 2 = rsinθ


By squaring and adding, we get


(0)2 + (2)2 = (rcosθ)2 + (rsinθ)2


0+4 = r2(cos2θ + sin2θ)


4 = r2


r = 2


cosθ= 0 and sinθ=1


Since, θ lies in first quadrant, we have



Thus, the required polar form is


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