Answer :

Given:


(3x-2iy)(2+i)2=10(1+i)


(3x-2yi)(22+i2+2(2)(i))=10+10i


We know that i2=-1


(3x-2yi)(4+(-1)+4i)=10+10i


(3x-2yi)(3+4i)=10+10i


Dividing with 3+4i on both sides



Multiplying and dividing with 3-4i







Equating Real and Imaginary parts on both sides we get




The values of x and y are .


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

Evaluate<imRS Aggarwal - Mathematics

Evaluate

<
RS Aggarwal - Mathematics

Evaluate:

RS Aggarwal - Mathematics

<img width=RS Aggarwal - Mathematics

<img width=RS Aggarwal - Mathematics

If <img widRD Sharma - Mathematics

<img width=RS Aggarwal - Mathematics

<img width=RS Aggarwal - Mathematics

If (1 + i)z = (1 RS Aggarwal - Mathematics

<img width=RS Aggarwal - Mathematics