Q. 2 B

Find the real val

Given:

(3x-2iy)(2+i)2=10(1+i)

(3x-2yi)(22+i2+2(2)(i))=10+10i

We know that i2=-1

(3x-2yi)(4+(-1)+4i)=10+10i

(3x-2yi)(3+4i)=10+10i

Dividing with 3+4i on both sides

Multiplying and dividing with 3-4i

Equating Real and Imaginary parts on both sides we get

The values of x and y are .

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