Q. 115.0( 2 Votes )
Find the modulus
Let Z = 4√2i - 4 = r(cosθ + isinθ)
Now, separating real and complex part , we get
-4 = rcosθ ……….eq.1
4√3 = rsinθ …………eq.2
Squaring and adding eq.1 and eq.2, we get
64 = r2
Since r is always a positive no., therefore,
r = 8
hence its modulus is 8.
now, dividing eq.2 by eq.1, we get,
Since , and . therefore the lies in second the quadrant.
Tanθ = -√3, therefore θ= .
Representing the complex no. in its polar form will be
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