Q. 23

# Solve the equatio

Answer :

Given:

|z|=z+1+2i

Let us assume z=x+iy

|x+iy|=x+iy+1+2i Equating Real and Imaginary parts on both sides we get

y+2=0

y=-2-----------------------(1) x2+(-2)2=(x+1)2

x2+4=x2+2x+1

2x=3  .

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