Answer :

Given:



Rationalising denominator




We know that i2=-1





i3–(-i)3=x+iy


2i3=x+iy


2i2.i=x+iy


2(-1)i=x+iy


-2i=x+iy


Equating Real and Imaginary parts on both sides we get


x=0 and y=-2


The values of x and y are 0 and -2.


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