Answer :

The integers between 100 and 600 divisible by 5 and leaves remainder 2 are 102, 107, 112, 117,…, 597.


To Find: Sum of the above AP


Here a = 102, d = 5, l = 597


a + (n - 1)d = 597


102 + 5(n - 1) = 597


(n - 1) = 99


n = 100


Now,



S = 50[204 + 495] = 50 × 699 = 34950


The sum of all such integers is 34950.


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