Answer :
The integers between 100 and 600 divisible by 5 and leaves remainder 2 are 102, 107, 112, 117,…, 597.
To Find: Sum of the above AP
Here a = 102, d = 5, l = 597
a + (n - 1)d = 597
⇒102 + 5(n - 1) = 597
⇒ (n - 1) = 99
⇒n = 100
Now,
⇒S = 50[204 + 495] = 50 × 699 = 34950
The sum of all such integers is 34950.
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