# Find the 23rd term of the AP 7, 3, 1, –1, –3, …

To Find: 23rd term of the AP

Given: The series is 7, 5, 3, 1, –1, –3, …

a1= 7, a2= 5 and d= 3–5= –2

(Where a=a1 is first term, a2 is second term, an is nth term and d is common difference of given AP)

Formula Used: an = a + (n - 1)d

So put n =23 in above formula, we have

a23= a1 + (23 - 1)(–2) = 7– 44 = –37

So 23rd term of AP is equal to –37.

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