Answer :

To Find: we need to find n when a_{n} = 0

Given: The series is 64, 60, 56, 52, 48, … and a_{n}= 0

a_{1}=64, a_{2}= 60 and d=60–64 = –4

(Where a=a_{1} is first term, a_{2} is second term, a_{n} is nth term and d is common difference of given AP)

Formula Used: a_{n} = a + (n - 1)d

a_{n}= 0 = a_{1} + (n–1)(–4)

0– 64 = (n–1)(–4) [subtract 64 on both sides]

– 64 = (n–1)(–4)

64 = (n–1)4 [Divide both side by ‘–‘]

16 = (n–1) [Divide both side by 4]

n = 17^{th} [add 1 on both sides]

The 17^{th} term of this AP is equal to 0.

Rate this question :

There are n A.M.sRD Sharma - Mathematics

If x, y, z are inRD Sharma - Mathematics

Insert 7 A.M.s beRD Sharma - Mathematics

The 10^{th</su}RD Sharma - Mathematics

Insert five numbeRD Sharma - Mathematics

The 4^{th</sup}RD Sharma - Mathematics

In an A.P. the fiRD Sharma - Mathematics

Insert 4 A.M.s beRD Sharma - Mathematics

Show that x^{2}RD Sharma - Mathematics

An A.P. consists RD Sharma - Mathematics