Answer :

To prove: a2(b + c), b2(c + a), c2(a + b) are in A.P.


Given: are in A.P.


Proof:are in A.P.


are in A.P.


are in A.P.


If each term of an A.P. is multiplied by a constant, then the resulting sequence is also an A.P.


Multiplying the A.P. with (abc)


, are in A.P.


are in A.P.


[(a2c + a2b)], [ab2 + b2c], [c2b + ac2] are in A.P.


On rearranging,


[a2(b + c)], [b2(c + a)] , [c2(a + b)] are in A.P.


Hence Proved


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

If <img widRS Aggarwal - Mathematics

In a potatoRD Sharma - Mathematics

A man accepRD Sharma - Mathematics

A manufactuRD Sharma - Mathematics

A man savesRD Sharma - Mathematics

A carpenterRD Sharma - Mathematics

A man startRD Sharma - Mathematics

The income RD Sharma - Mathematics

If tn Mathematics - Exemplar

Fill in the blankMathematics - Exemplar