# <span lang="EN-US

Hint: - In the question it is mentioned that the production increases by a fixed number every year.

So it is an A.P. (a1, a2, a3, a4, ........an - 1, an).

Given: -

The 3rd year production is 6000 units

So,

a3 = 6000

We know that an = a + (n - 1) ×d

a3 = a + (3 - 1)×d

6000 = a + 2d

The 7th year production is 7000 units

So,

a7 = 7000

a7 = a + (7 - 1)×d

7000 = a + 6d

From equations (1)&(2) we get,

6000 - 2d = 7000 - 6d

4×d = 1000

d = 250

From equations (1)&(2) we get,

a = 5500

i. Production in the first year = a = 5500

5500 units were produced by the manufacturer of TV sets in the first year.

ii. Production in the 10th year = a10 = a + (10 - 1)×d

a10 = 5500 + (9) ×250

= 7750

7750 units were produced by the manufacturer of TV sets in the 10th year.

iii. Total production in seven years = a1 + a2 + a3 + a4 + a5 + a6 + a7

s7 = 43750

A total of 16, 250 units was produced by the manufacturer in 7 years.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses
RELATED QUESTIONS :

If <img widRS Aggarwal - Mathematics

In a potatoRD Sharma - Mathematics

A man accepRD Sharma - Mathematics

A manufactuRD Sharma - Mathematics

A man savesRD Sharma - Mathematics

A carpenterRD Sharma - Mathematics

A man startRD Sharma - Mathematics

The income RD Sharma - Mathematics

If tn Mathematics - Exemplar

Fill in the blankMathematics - Exemplar