Answer :
Here we are given
A = {5, 6, 7, 8 }
B = {–11, 4, 7, –10,–7, –9,–13 }
f = {( x,y) : y = 3 - 2x, x A, y
B }
so we can find
f = {( x,y) : y = 3 - 2x, x A, y
B }
f(5) = 3- 2×5 = 3-10 = -7
f(6) = 3 – 2×6 = 3-12 = -9
f(7) = 3 – 2×7 = 3-14 = -11
f(8) = 3 – 2×8 = 3- 16 = -13
(i) the elements of f are
From the above expression we get that
f = {(5,-7),(6,-9),(7,-11),(8,-13)}
(ii) co-domain
The co-domain is B and it can be given as
Codomain B = {-11,4, 7,-10,-7,-9,-13}
(iii) Range
Range may be defined as the image of A in B present in the function.
Range of f = {-7,-9,-11,-13}
(iv) type of function
From the above data and the diagram it’s clear that the given function is a one-one function as all the element A has a unique and single image in B. it’s not a onto function as the range is not same as the co-domain .
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