Q. 105.0( 1 Vote )

Let A = {5, 6, 7,

Answer :

Here we are given


A = {5, 6, 7, 8 }


B = {–11, 4, 7, –10,–7, –9,–13 }


f = {( x,y) : y = 3 - 2x, x A, y B }


so we can find


f = {( x,y) : y = 3 - 2x, x A, y B }


f(5) = 3- 2×5 = 3-10 = -7


f(6) = 3 – 2×6 = 3-12 = -9


f(7) = 3 – 2×7 = 3-14 = -11


f(8) = 3 – 2×8 = 3- 16 = -13


(i) the elements of f are


From the above expression we get that


f = {(5,-7),(6,-9),(7,-11),(8,-13)}


(ii) co-domain


The co-domain is B and it can be given as


Codomain B = {-11,4, 7,-10,-7,-9,-13}


(iii) Range


Range may be defined as the image of A in B present in the function.


Range of f = {-7,-9,-11,-13}


(iv) type of function



From the above data and the diagram it’s clear that the given function is a one-one function as all the element A has a unique and single image in B. it’s not a onto function as the range is not same as the co-domain .


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