Q. 95.0( 1 Vote )

# For A = {5,10,15,

The given statement A \ (B \ C) = (A \ B) \ C can be rewritten as

A \ (B\C) = (A \ B) \ C.

Here we have to compare the elements obtained from the difference or compliment of two sets and check whether they are associative in nature or not.

Given data

A = {5, 10, 15, 20};

B = {6, 10, 12, 18, 24}

C = {7, 10, 12, 14, 21, 28}

L.H.S

For easy solving we can spit the statement A \ (B\C) into two halves where first we will find the difference between B and C after we will find difference between set A and the result obtained from the difference of B and C

So (B\C) = {6, 10, 12, 18, 24} \ {7, 10, 12, 14, 21, 28}

= {6, 18, 24}

A \ (B\C) = {5, 10, 15, 20} \ {6, 18, 24}

= {5, 10, 15, 20}…………. (i)

R.H.S

(A \ B) \ C again we will split this statement in two to find the difference result. First of all we will find the difference between A and B and after that another difference operation will be done between the results obtained from (A \ B) and C

Using the data given

(A \ B) = {5, 10, 15, 20} \ {6, 10, 12, 18, 24}

= {5, 10, 15, 20}

(A \ B) \ C = {5, 10, 15, 20} \ {7, 10, 12, 14, 21, 28}

= {5, 15, 20}…………. (ii)

From (i) and (ii) it’s clear that L.H.S. and R.H.S aren’t same so

A \ (B\C) = (A \ B) \ C is a false statement.

i.e A \ (B\C) ≠ (A \ B) \ C

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