Let f = {(2, 7),

Here we are given that

f = {(2, 7), (3, 4), (7, 9), (–1, 6), (0, 2), (5, 3)}

A = { –1, 0, 2, 3, 5, 7 }

B = { 2, 3, 4, 6, 7, 9 } where f:A→ B

Here from the above expression the range of the function can be given as

Range of f = {7, 4, 9, 6, 2, 3} = B

So it clear that it is an onto function, again the mapping shows that every element of A is mapped to an unique element of B and no two elements of A is linked with a single element of B so it’s a one-one function too.

Hence its clear that the expression is a one-one and onto function