Q. 21 B4.1( 55 Votes )

# Fill in the blanks in the following conversions:

(i) 1 km = ...................... mm = ...................... pm

(ii) 1 mg = ...................... kg = ...................... ng

(iii) 1 mL =...................... L = ...................... dm3

Answer :

(i) We know the basic relation that

1km = 1000m

1 m = 1000 mm

Therefore 1 km = 1000×1000

= 10^{6} mm

We also know that

1 m = 10^{12}pm

Therefore 1 km = 1000× 10^{12} pm

= 10^{15}pm

(ii) We know the basic relation that

1 kg = 1000 g

1 g = 1000 mg

So, 1 mg = 10^{-3}g

Therefore 1 mg = 10^{-3} × 10^{-3} kg

= 10^{-6} kg

1 g = 10^{9}ng

1000 mg = 10^{9} ng

1 mg = [10^{9}]/10^{3} ng

= 10^{6} ng

(iii) We know the basic relation that

1 L = 1000 ml

∴ 1 ml = 10^{-3} L

1 ml = 10^{-3} dm^{3}

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