Answer :


Percentage of Iron in the oxide = 69.9%

Percentage of oxygen in the oxide = 30.1%

Finding Empirical Formula:

To determine the empirical formula of iron oxide, we need to find the simplest whole number ratio.

Therefore, the empirical formula for iron oxide is Fe2O3.

Finding Molecular Formula:

Empirical Formula Mass = [55.84×2] + [16×3]

= 111.68 + 48

= 159.68g

Molecular Mass [given] = 159.69g

n = [Molecular Mass]/ [Empirical Formula Mass]

= 159.69/159.68

= 1

Molecular Formula = n × Empirical Formula

= 1 × Fe2O3.

= Fe2O3

Therefore, the Molecular Formula is Fe2O3.

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