Answer :

Given:

Percentage of Iron in the oxide = 69.9%


Percentage of oxygen in the oxide = 30.1%


Finding Empirical Formula:


To determine the empirical formula of iron oxide, we need to find the simplest whole number ratio.



Therefore, the empirical formula for iron oxide is Fe2O3.


Finding Molecular Formula:


Empirical Formula Mass = [55.84×2] + [16×3]


= 111.68 + 48


= 159.68g


Molecular Mass [given] = 159.69g


n = [Molecular Mass]/ [Empirical Formula Mass]


= 159.69/159.68


= 1


Molecular Formula = n × Empirical Formula


= 1 × Fe2O3.


= Fe2O3


Therefore, the Molecular Formula is Fe2O3.


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