# Calculate the amo

The reaction of carbon with oxygen is given as follows:

(i) By observing the above equation, it is understood that when 1 mole of carbon is burnt in air, then the amount of carbon dioxide produced is 44 g [Molecular Mass of carbon dioxide].

(ii) In the above equation 32 g of oxygen react with 1 mole of carbon, then 44 g of carbon dioxide is produced.

32 g of Oxygen → 44 g of Carbon Dioxide
16 g of Oxygen → X g of Carbon Dioxide

X = [44×16]/32

= 22 g

Therefore, 16 g of oxygen when reacted with 1 mole of carbon we get 22 g of CO2.

(iii) Even though 2 moles of carbon is available for reaction but 16 g of oxygen can react with only 0.5 moles of carbon to give 22 g of CO2. In this oxygen acts as limiting reagent and carbon acts as an excess reagent. So 1.5 moles carbon would be left un-reacted.

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