Answer :

Given:

Atomic Mass of First Isotope of Chlorine = 34.9689g


Natural Abundance of First Isotope of Chlorine, Pa1 = 75.77%


= 0.7577


Total Atomic Mass of 1st Isotope, Ma1 = 34.9689×0.7577


= 26.4959g


Atomic Mass of Second Isotope of Chlorine = 36.9659g


Natural Abundance of Second Isotope of Chlorine, Pa2 = 24.23%


= 0.2423


Total Atomic Mass of 2nd Isotope, Ma2 = 36.9659×0.2423


= 8.9568g

  Avg. Atomic Mass of Chlorine =
=(26.4959 gm + 8.9568 gm)

=35.4527 gm.

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