Answer :

TRUE


Let AB,BC,CD,AD(sides) and AC(diagonal) be given.


Draw ΔABC using SSS construction.


Now, we have to locate the 4th point D. this ‘D’ would be on the side opposite to B with reference to AC.


So, with A as centre draw an arc of radius of length equal to AD.


Now, with C as centre draw an arc of radius of length equal to CD.


The intersection of these 2 arcs is D. Mark D and complete ABCD


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