Answer :

(i) As we have (x + 6)(x+6)


(x + 6)(x + 6) = (x + 6)2


By using the formula;


[(a + b)2 = a2 + b2 + 2ab]


We get,


(x + 6)2 = x2 + (6)2 + 2× (x) × (6)


= x2 + 36 + 12x


By arranging the expression in the form of descending powers of x we get;


= x2 + 12x + 36


(ii) Given;


(4x + 5y)(4x + 5y)


By using the formula;


[(a + b)2 = a2 + b2 + 2ab]


We get,


(4x + 5y)(4x + 5y) = (4x + 5y)2


(4x + 5y)2 = (4x)2 + (5y)2 + 2 × (4x) ×(5y)


= 16x2 + 25y2 + 40xy


(iii) Given,


(7a + 9b)(7a + 9b)


By using the formula;


[(a + b)2 = a2 + b2 + 2ab]


We get,


(7a + 9b)(7a + 9b) = (7a + 9b)2


(7a + 9b)2 = (7a)2 + (9b)2 + 2 × (7a) × (9b)


= 49a2 + 81b2 + 126ab


(iv)


By using the formula (a + b)2


We get;





(v) (x2 + 7)(x2 + 7)


By using the formula (a + b)2


We get;


(x2 + 7)(x2 + 7) = (x2 + 7)2


= (x2)2 +(7)2 + 2 × (x2) × (7)


= x4 + 49 + 14x2


(vi)


By using the formula (a + b)2


We get;






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