# Find each of the

(i) As we have (x + 6)(x+6)

(x + 6)(x + 6) = (x + 6)2

By using the formula;

[(a + b)2 = a2 + b2 + 2ab]

We get,

(x + 6)2 = x2 + (6)2 + 2× (x) × (6)

= x2 + 36 + 12x

By arranging the expression in the form of descending powers of x we get;

= x2 + 12x + 36

(ii) Given;

(4x + 5y)(4x + 5y)

By using the formula;

[(a + b)2 = a2 + b2 + 2ab]

We get,

(4x + 5y)(4x + 5y) = (4x + 5y)2

(4x + 5y)2 = (4x)2 + (5y)2 + 2 × (4x) ×(5y)

= 16x2 + 25y2 + 40xy

(iii) Given,

(7a + 9b)(7a + 9b)

By using the formula;

[(a + b)2 = a2 + b2 + 2ab]

We get,

(7a + 9b)(7a + 9b) = (7a + 9b)2

(7a + 9b)2 = (7a)2 + (9b)2 + 2 × (7a) × (9b)

= 49a2 + 81b2 + 126ab

(iv)

By using the formula (a + b)2

We get;

(v) (x2 + 7)(x2 + 7)

By using the formula (a + b)2

We get;

(x2 + 7)(x2 + 7) = (x2 + 7)2

= (x2)2 +(7)2 + 2 × (x2) × (7)

= x4 + 49 + 14x2

(vi)

By using the formula (a + b)2

We get;

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