Answer :



BEST is a rhombus,
So, TS || BS
∠SBE = ∠BST = 40° (alternate interior angles)
As Diagonals of a rhombus bisect at right angles.
∠y = 90°

In Δ TSO,
∠STO + ∠OST = ∠EOS (Exterior angle property)
⇒ x + 40° = 90°
 ⇒ x = 90° - 40° 
 ⇒ x = 50°  

So, y - x = 90° - 50°  
        
             = 
40°

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