Q. 414.5( 2 Votes )

In the figure, BEST is a rhombus. Then the value of y-x isA. 40°B. 50°C. 20°D. 10°

BEST is a rhombus,
So, TS || BS
∠SBE = ∠BST = 40° (alternate interior angles)
As Diagonals of a rhombus bisect at right angles.
∠y = 90°

In Δ TSO,
∠STO + ∠OST = ∠EOS (Exterior angle property)
⇒ x + 40° = 90°
⇒ x = 90° - 40°
⇒ x = 50°

So, y - x = 90° - 50°

=
40°

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