Answer :

In the rhombus,

BAM = 700


Also, we know that the diagonals of a rhombus bisect at 900


AOM = 90


Now, in ΔAOM,


AOM + OMA + MOA = 1800


90 + OMA + 70 = 1800


AME = OMA = 200


Also,


The sides in the rhombus are equal.


Ans, we know, equal sides make equal angles.


⇒ ∠AEM = 200


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

The angle betweenRD Sharma - Mathematics

A playground is iNCERT - Mathematics Exemplar

Diagonals of a paRD Sharma - Mathematics

The perimeter of RD Sharma - Mathematics