Answer :

Let MODE be the parallelogram and Q be the point of intersection of the bisector of M and O


The figure is attached below:



Now, in a parallelogram, the adjacent angles are supplementary.


EMO + DOM = 180°


1/2 (EMO + DOM) = 1/2 180°


1/2EMO + 1/2DOM = 1/2 180°


QMO + QOM = 90°


Now, in ΔMOQ,


QMO + QOM + MQO = 1800


900 + MQO = 1800


MQO = 900


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