Answer :

Given:

RQY = 60°


RQY and RQP form a linear pair


RQP = 180° - RQY = 120°


RQP =120°


Now, in a parallelogram, the opposite sides are equal,


RQP = S = 120°


Similarly, P = R


Now, from the angle sum property of a quadrilateral,


P + R + Q + S = 360°


P + R + 120° + 120° = 360°


2P = 120°


P = 60°


R = 60°


Now,


Opposite sides of the parallelogram are equal.


SR = PQ = 15 cm


Also, PS = QR = 11 cm


And, the diagonals of the parallelogram bisect each other.


Hence, PR = 2×PQ = 2×6 = 12 cm.


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

The angle betweenRD Sharma - Mathematics

A playground is iNCERT - Mathematics Exemplar

Diagonals of a paRD Sharma - Mathematics

The perimeter of RD Sharma - Mathematics