Answer :

In Rhombus ABCD,


AO = OP + PA = 2+2 = 4 units.


And, OB = OQ + QB = 2 + 1 = 2 units.


Now,


We know that the diagonals of the rhombus bisect at 900


in ΔOAB,


AB2 = OA2 + OB2


AB2 = 42 + 32


AB = √25


AB = 5 units.


Now, AB is also the diameter of the semi-circle.


radius of the circle will be 2.5 units.


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