abx 2 + (b 2 - ac)x - bc = 0 abx 2 + b 2 x - acx - bc = 0 bx(ax + b) â c(ax + b) = 0 (ax + b)(bx â c) = 0

Q. 49

Using factorizat

Answer :

abx ² + (b ² - ac)x - bc = 0
abx ² + b ² x - acx - bc = 0
bx(ax + b) â c(ax + b) = 0
(ax + b)(bx â c) = 0

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