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Let the faster pipe fill the tank in ‘a’ min.

Given: Slower pipe fills it in ‘a + 5’ min.

To find: Time taken by each pipe.

Method Used:

1) Multiply the coefficient of x2 and constant term.

2) factorise the result obtained in step 1.

3) Now choose the pair of factors in such a way that after adding or subtracting(splitting) them

You get coefficient of x.

Explanation:

The faster pipe fills the tank in ‘a’ min.

Slower pipe fills it in ‘a + 5’ min.

Given, the pipes running together can fill a tank in In 1 min, part of tank filled The faster pipe fills in 1 min The slower pipe fills in 1 min According to the question,  100(a + a + 5) = 9(a2 + 5a)

200a + 500 = 9a2 + 45a

9a2 – 155a - 500 = 0

9a2 – 180a + 25a - 500 = 0

9a (a – 20) + 25(a – 20) = 0

(9a + 25) (a – 20) = 0

a = 20 mins

Slower pipe will fill it in a+5 = 25 min

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